Question

A jogger moves 500 m in 2 minutes and next 1000 m in 30 s on the same straight path. What is his average speed?

Answer 1

Answer

hope it helps you

mark me brainliest pls

Answer 2

Given :-

A jogger moves 500 meters in 2 minutes and next 1000 meters in 30 seconds .

The direction of motion is straight

Required to find :-

• Average speed

Formula used :-

$\boxed{ \sf{ \red{average \: speed = } \green{ \frac{total \: distance}{total \: time \: taken} }}} \bigstar$

Solution :-

Given information :-

A jogger moves 500 meters in 2 minutes and next 1000 meters in 30 seconds .

we need to find the average speed .

From the given data we can conclude that ;

Case - 1

Distance ( d1 ) = 500 meters

Time ( t1 ) = 2 minutes ( 120 seconds )

Case - 2

Distance ( d2 ) = 1000 meters

Time ( t2 ) = 30 seconds

Since,

The S.I. unit of speed is m/s

Let's time ( t1 ) from minutes 10 seconds

So,

• 1 minute = 60 seconds

2 minutes = ? seconds

=> 2 x 60

=> 120

2 minutes = 120 seconds

Using the formula ;

$\: \boxed{ \sf{ \red{average \: speed = } \green{ \frac{total \: distance}{total \: time \: taken} }}} \bigstar$

Here,

Total distance = d1 + d2

=> 500 meters + 1000 meters

=> 1500 meters

• Total distance = 1, 500 meters

Similarly,

Total time taken = t1 + t2

=> 120 seconds + 30 seconds

=> 150 seconds

• Total time taken = 150 seconds

Substituting the values ;

$\rightarrowtail \rm average \: speed = \dfrac{1500 \: meters}{150 \: seconds} \\ \\ \rightarrowtail \rm average \: speed = 10 \: m {s}^{ - 1}$

Therefore,

Average speed of the jogger is 10 m/s

Additional information :-

Speed is a scalar quantity .

Velocity is a vector quantity .

Speed requires only magnitude but not direction .

Velocity requires both magnitude and direction .

The scenario mentioned above in the question tells about the velocity because it is travelling in a straight path .

This states the fact that ;

In some cases we can take velocity in terms of speed but we can't take speed in the terms of velocity