a joker cap is in the form of a right circular cone of base radius 7 cm and height 27 cm find the area of the sheet required to make 10 such caps
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Answered by
5
r = 7cm
h = 27cm
l = √r² + h²
= √49+27²
= √49+729
= 27.8cm
C.S.A of one cone = πrl
= 22/7 × 7 × 27.8
= 22×27.8
= 611.6cm²
Sheet required for 10 such cones = area of one cone × 10
= 611.6 × 10
= 6116cm²
h = 27cm
l = √r² + h²
= √49+27²
= √49+729
= 27.8cm
C.S.A of one cone = πrl
= 22/7 × 7 × 27.8
= 22×27.8
= 611.6cm²
Sheet required for 10 such cones = area of one cone × 10
= 611.6 × 10
= 6116cm²
Answered by
10
Solution:
Given radius = 7 cm
Given height = 24 cm
To find:
The Curved Surface Area of Cone -
We know that;
=> πrl
Let's find the value of 'l' at first;
Since,
=> l = √r^2 + h^2
=> l = √7^2 + 24^2
=> l = √49 + 576
=> l = √625
=> l = √25^2
Hence, => l = 25 cm
Now,
=> πrl
=> 22/7 × 7 × 25
=> 22 × 25
=> 550 cm^2
Also, area of sheet required to make 10 such caps;
=> 550 × 10
=> 5500 cm^2
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