A joker cap is in the form of a right circulara cone of a base rafious 7cm qnd height 24 cm find area of sheet requied to make 10 such caps
Answers
Answer:
Step-by-step explanation:
radius = 7cm
height = 24 cm
l =√r² +h²
l =√7² + 24²
l = √49 + 576
l = √625
l = 25
Curved surface area of one conical cap =
πrl= (22/7)×(7)×25
= 550 cm ²
Curved surface area of 10 conical caps = 10 × 550 cm ²= 5500 cm²
∴ the area of sheet required to make 10 conical caps is 5500 cm
Answer:
Step-by-step explanation:
given radius of base=7cm
and height of joker cap=24cm
to find the area of sheet required to make 10 such caps
(slant height)^2=(radius)^2+(height)^2
(l)^2=(7)^2+(24)^2
l square=49+576
l square=625
l=25
now,curved surface of cone=pi*r*l
=22/7*7*25
=22*25
= 550cm^2
area of sheet required to make 10 such caps=550*10
5500cm^2