A joker cap is in the form of cone od radius 7cm andheight 24cm find the area of sheet required to make 10 such caps
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Area of sheet required to make 1 cap = Curved surface area of cone
CSA of cone=22/7rl
l=sq.root(r2 + h2)
=(49+576)
=625
Therefore l=25
CSA of cone=22/7*7*25
=22*25
=550 sq.cm
Area of sheet required to make 10 such caps=
CSA of 1 cone * 10=550*10=5500sq.cm
CSA of cone=22/7rl
l=sq.root(r2 + h2)
=(49+576)
=625
Therefore l=25
CSA of cone=22/7*7*25
=22*25
=550 sq.cm
Area of sheet required to make 10 such caps=
CSA of 1 cone * 10=550*10=5500sq.cm
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