Physics, asked by areebakulsum21, 4 months ago

A joker moves 5 steps forward and 3 steps backwards. If each step is of one meter and he takes one second to cover one step what would be the distance travelled and the displacement covered by the joker after 20s.

Answers

Answered by shabnamnizam
1

Answer:

they covered 19 m in 20 sec and there was 21 steps in 19 m

Answered by prachikumari21
3

Answer:

Distance covered with 1 step = 1 m.

Time taken = 1 s .

Time taken to move first 5 m forward = 5 s .

Time taken to move 3 m backward = 3 s.

Net distance covered = 5-3=2 m.

Net time taken to cover 2 m = 8 s.

Joker covers 2 m in 8 s .

Joker covered 4 m in 16 s .

Joker covered 6 m in 24 s.

Joker covered 8 m in 32 s.

In the next 5s, the joker will cover a distance of

5m and a total distance of 13m and falls into the

pit.

Net time taken by the joker to cover 13 m=

32+5 37 s.

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