Question

Calculate the acceleration if an engine starts from rest and moves with uniform
acceleration, attaining a speed of 40 km/h in 10 minutes.​

Answer 1

Answer:

$a=0.0185m/s^2$

Explanation:

Initial speed of the engine, u = 0 km (Because train starts from the rest.

Final speed of the engine, v = 40 km/h =  × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

$a=\frac{v-u}{t}$

Putting all the values, we get

$a=\frac{11.11-0}{600}$$=\frac{11.11}{600}$

Therefore, $a=0.0185 m/s^2$

Answer 2

Answer:

The required acceleration is 0.0185 m/s²

Explanation:

Given :

An engine starts from rest and moves with uniform  acceleration, attaining a speed of 40 km/h in 10 minutes.​

To find :

the acceleration

Solution :

• initial velocity = u

u = 0 km/h = 0 m/s

• final velocity = v

v = 40 km/h

v = 40 × 5/18 m/s

v = 200/18 m/s

v = 100/9 m/s

• time taken = t

 t = 10 minutes

 t = 10 × 60 sec

 t = 600 sec

We know,

Acceleration is the rate of change of velocity.

$\longrightarrow \sf a=\dfrac{v-u}{t}$

Substituting the  values,

$\tt a=\dfrac{\dfrac{100}{9}}{600} \\\\ \tt a=\dfrac{1}{9 \times 6} \\\\ \tt a=\dfrac{1}{54} \\\\ \tt a=0.0185 \ m/s^2$

Therefore, the acceleration is 0.0185 m/s²