a joker’s cap is in the form of a right circular cone of base radius 7cm and height 24cm. find the area of the sheet required to make 15 such caps?
Answers
Answer:
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Step-by-step explanation:
Given:-
a joker’s cap is in the form of a right circular cone of base radius 7cm and height 24cm.
To find:-
find the area of the sheet required to make 15 such caps?
Solution:-
A joker's cap is in the form of a right circular cone
Radius of the base of the cap=(r)=7 cm
Height of the cap =(h)=24 cm
Slant height of the cap =(l)=√(h^2+r^2) units
=>l=√(24^2+7^2)
=>l=√(576+49)
=>l=√625 cm
=>l=25 cm
Slant height of the cap =(l)=25 cm
Required area of the sheet of paper for making a joker's cap
=Curved Surface Area of the Cone
=πrl sq.units
=>(22/7)×7×25 sq.cm
=>(22×7×25)/7 sq.cm
=>22×25 sq.cm
=>550 sq.cm
Area of the sheet of paper for making a joker's cap=550 sq.cm
given number of such caps =15
Area of the sheet of paper for making 15 such caps=550×15=8250 sq.cm
Answer:-
the area of the sheet required to make 15 such caps =8250 sq.cm
Used formula:-
Curved surface area of the right circular cone
=πrl sq.units
Where,
π=22/7
r=radius of the cone
l=slant height of the cone
l=√(h^2+r^2) units
h=height of the cone