Question

A joker's cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.​

Answer 1

Answer:

Base radius (r) = 7 cm

Height (h) = 24 cm

therefore space Slant height (l) = square root of straight r squared plus straight h squared end root

equals square root of left parenthesis 7 right parenthesis squared plus left parenthesis 24 right parenthesis squared end root equals square root of 49 plus 576 end root

equals square root of 625 equals 25 space cm

therefore space space Curved surface area of a cap = πrl

equals 22 over 7 cross times 7 cross times 25 equals 550 space cm squared

∴ Curved surface area of 10 caps = 550 x 10 = 5500 cm2

Hence, the area of the sheet required to make 10 such caps is 5500 cm2.

Step-by-step explanation:

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@queenofhearts here..

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Answer 2

Answer:

Step-by-step explanation:

radius = 7cm height = 24 cm

1 =√r² +h²

1 = -√7² +24² 1 = √49 + 576

1 = √625

1 = 25

Curved surface area of one conical cap = Trl= (22/7)×(7)×25 = 550 cm ² 2

Curved surface area of 10 conical caps = 10 x 550 cm 2= 5500 cm²

:: the area of sheet required to make 10 conical caps is 5500 cm²