A joker's cap is in the form of a right circular cone of base radius 7cm and height 24cm . find the area of the sheet required to make 10 such caps .
Answers
Answered by
1
Answer:
5500 cm2
Step-by-step explanation:
It is given that
Radius of the cap = 7cm
Height of the cap = 24cm
We know that
The slant height of the cap
l = √ (r2 + h2)
By substituting the values
l = √ (72 + 242)
On further calculation
l = √ (49 + 576) = √ 625
So we get
l = 25cm
We know that
The curved surface area of one cap = πrl
By substituting the values
The curved surface area of one cap = (22/7) × 7 × 25
So we get
The curved surface area of one cap = 550 cm2
So the curved surface area of 10 conical caps = 10 × 550 = 5500 cm².
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Answered by
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Answer:
25320 cm or 2 km 53 m 20 cm
Step-by-step explanation:
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