Question

A joker's cap is in the form of right circular cone whose radius 7cm and height is 24 cm and find the area of the sheet required to make 10 such caps

Answer 1

radius = 7cm 
height = 24 cm 

l =√r² +h²
l =√7² + 24²
l = √49 + 576
l = √625
l = 25 

Curved surface area of one conical cap = 
πrl= (22/7)×(7)×25
= 550 cm ²


Curved surface area of 10 conical caps = 10 × 550 cm ²= 5500 cm²
 
∴ the area of sheet required to make 10 conical caps is 5500 cm² 

Answer 2

HELLO DEAR,



GIVEN:-
radius of cone r = 7cm
height of cone h = 24cm
slant height l = √(24² + 7²) = √(576 + 49) = √625

l = 25cm

since, joker's cap is in the form of right circular cone

so, area of joker's cap = πrl

=> 22/7 × 7 × 25

=> 22 × 25

=> 550cm²

so, curved surface area of 1 joker's cap = 550cm²

curved surface area 10 joker's cap = 10 × 550 = 5500cm²

I HOPE IT'S HELP YOU DEAR,
THANKS