Question

A joker’s cap is in the form of right circular cone whose base radius is 7 cm and height is 24 cm. Find the area of the sheet required to make 10 such caps.

Answer 1

HELLO DEAR,



GIVEN:-
radius of cone r = 7cm
height of cone h = 24cm
slant height l = √(24² + 7²) = √(576 + 49) = √625

l = 25cm


since, joker's cap is in the form of right circular cone

so, area of joker's cap = πrl

=> 22/7 × 7 × 25

=> 22 × 25

=> 550cm²

so, curved surface area of 1 joker's cap = 550cm²

curved surface area 10 joker's cap = 10 × 550 = 5500cm²


I HOPE IT'S HELP YOU DEAR,
THANKS

Answer 2

Solutions :-

Given :
Radius = r = 7 cm
Height = h = 24 cm

Find the slant height (l) of circular cone :-

l = √(24² + 7²)
= √(476 + 49)
= √(625) = 25


Find area of sheet :-

Curved surface area of right circular cone = πrl sq. unit
= 22/7 × 7 × 25 cm²
= 22 × 25 cm²
= 550 cm²


Find the area of the sheet required to make 10 such caps :-

Area of the sheet required to make 1 cap = 550 cm²
Area of the sheet required to make 10 such caps = 550 × 10 = 5500 cm²


Hence,
The area of the sheet required to make 10 such caps = 5500 cm²

_______________________

✯ @shivamsinghamrajput ✯