Question

a juggler maintains 10 balls in motion make each of them to rise at a height of 8 m from his hand to give proper distance between them the time interval made by jugular would be

Answer 1

Answer:

the right answer is given in the solution above.

Answer 2

Corrected Height : 80 m

Answer:

Final Answer :Gap of 0.8 s

Steps:

1) We need to find time interval between any two balls out of 10 balls such that all are evenly space out in surroundings. That is, when first ball is at end then last ball is at start of motion/journey .

2) Displacent ,S = 80 m

Acceleration due to gravity, a = -10m/s^2

time to reach max height, t =?

Final velocity, v = 0

at Max h We know that,

${v}^{2} - {u}^{2} = 2as \\ = > {0}^{2} - {u}^{2} = 2 \times - 10 \times 80 \\ = > u = 40m/s$

3) Time period of motion,

$T = 2u/g \\= \frac{2 \times 40  }{10} = 8 \: s$

We need to uniformly divide this time for 10 balls,

=> Time gap = T/10 = 8/10= 0.8 s