how to find the more stable among these two?
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FaZe:
need tp think (^_^)/
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Answered by
1
Where repulsion is less, that compound is more stable, and it is first which is more stable.
yeah
i couldnt get the ans
dekho vahan p H-H k bech p repulsion jyada hoga
repulsion k karan stability decrease hogi
oo u r right
hanjiii
tysm
good
thnku
मुझे लगता h.. यह triple bond का खेल h!!
Answered by
2
Hope u can understand it better.
============================
=> In Cyanide bond,..
The bond between C and N is 1 sigma and 2 pi bond.
This pi bond between C and N makes the come closer and have a strong bond and can't be broken easily!!
But in Carbo - amine group (-C-(NH2)3) bond, there is no such pi bonds. Thus, the bond can be easily broken in comparison to the cyanide bond.
More stronger bond, more stable it will be.
Thus, the - CN bond is more stronger and stable than - C-(NH2)3.
___________________________
Hope you got it easily.
Proud to help you
============================
=> In Cyanide bond,..
The bond between C and N is 1 sigma and 2 pi bond.
This pi bond between C and N makes the come closer and have a strong bond and can't be broken easily!!
But in Carbo - amine group (-C-(NH2)3) bond, there is no such pi bonds. Thus, the bond can be easily broken in comparison to the cyanide bond.
More stronger bond, more stable it will be.
Thus, the - CN bond is more stronger and stable than - C-(NH2)3.
___________________________
Hope you got it easily.
Proud to help you
thnx for the brainliest one
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