Question

A juggler throws a ball into air. he throws one whenever the previous one is at its highest point. how high do the ball rise if he throws n balls in each seconds?

Answer 1

Final Velocity = v = 0

Initial Velocity = u

Time = 1/n seconds

0 = u - g*1/n

g/n = u

Now applying third equation of motion,

v2 = u2 - 2gH

0 = g/n * g / n - 2gH

-(g/n)2 = - 2gH

g2/n2 = 2gH

g/n2 = 2H

H = g/2n2

Answer: g/ 2n2

Cheers

Best of Luck

Answer 2

Answer:

Here's ur ans............