Question

A juggler tosses a ball up in the air with initial speed u. at the instant it reaches its maximum height H, he tosses up a seconds ball with same initial speed. The two balls will collide at a height.

Answer 1

Answer:

Let the Displacement be S1 and S2 for the 2 balls

According to the question firstly the Juggler tosses a ball with speed ( u ) and the ball reaches the maximum height ( H ) and now that ball will fall downwards .

So ,, for the first ball S1 = 1/2×gt² 

For second ball which is also thrown upward with velocity ( u )

S2 = ut - 1/2×gt² 

=> S1 + S2 = H

→ 1/2×gt²  + ut - 1/2×gt²  = H

ut = H. ........... ( i )

=>> H = u²/ 2g ........( ii )

Then = t = u/2g

putting these values in S2 so that we could know that where the balls will collide .

S2 = u×u/2g - 1/2g×u² /4g

=> 3u² ÷ 4g

3H/4 .