Question

a junction of two highways is patrolled by two cars, one on each road. each car covers a distance of 5 km on either side of the junction on its road. if the speeds of the 2 cars are 50 km/hr and 75 km/hr and they start at the junction at 6 a.m. from same point, when will they meet next?

Answer 1

Let the cars be labeled A and B respectively.

Car A = 50 km/h

Car B = 75 km/h

Distance for each = 5 km

Time taken = Distance / Speed.

Time for A = 5/50 = 0.1 hrs

This in minutes is = 0.1 × 60 = 6 minutes

Time for B = 5/75 = 1/15 hrs

This in minutes is = 1/15 × 60 = 4 minutes

To get time taken for them to meet, we get the LCM Of their times.

LCM of 6 and 4 is 12

So they meet again after 12 minutes.

We add this to 6am to get :

6.00 + 12 = 6:12 a.m

Answer 2

Answer:

6:24

Step-by-step explanation:

time to cover 5 km at 50 and 75 km/hr

5/50=6 min

5/75=4 min

but they return to a junction back also so

6 min extra

4 min extra

total = 12 and 8

lcm (12,8)=24

hence 6:24