Question

a kayaker moves 32 meters northward, then 6 meters southward, and finally 16 meters northward. whta is the distance moved? what is the magnitude and direction of the displacement?

Answer 1

Answer:

50 metres.

Explanation:

Given that a kayaker moves 32 meters northward then 6 meters southward finally 24 meters northward

To calculate the displacement, let assume that

Northward = positive

Southward = negative

Displacement = 32 – 6 + 24

Displacement = 56 – 6

Displacement = 50 metres

The direction of the displacement will be northward.

While the distance will be:

Distance = 32 + 6 + 24 = 62 metres

Answer 2

The distance travelled is 52 meters and displacement is 42 meters in North direction.

GIVEN

A kayaker moves 32 meters northward, then 6 meters southward, and finally 16 meters northward.

TO FIND

Distance moved

Magnitude and direction of displacement

SOLUTION

We can simply solve the above problem as follows;

We know that, Distance is the total area travelled by the body.

So,

Total distance travelled will be equal to the sum of the complete area covered by the kayaker

Therefore,

Distance travelled = 32 + 6 + 16 = 52 meters

We know that,

Displacement is the measure of an object's final position with respect to its initial position. Displacement is the shortest distance between initial and final position of the object.

Displacement = OA + AD = 32 + 10 = 42 meters North.

Hence, The distance travelled is 52 meters and displacement is 42 meters in North direction.

Picture for reference.

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