Question

a ki power minus 1 into B ki power minus 1 upon 1 upon a b ki power -1 indices maths answer
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Answer 1

Answer:

$\frac{1}{a^{2}b^{2}}$

Step-by-step explanation:

If I am getting this question right then you need to find the value of

$\frac{a^{-1}\times b^{-1}}{1/(ab)^{-1}}$

$=a^{-1}\times b^{-1}\times (ab)^{-1}$

$=a^{-1}\times b^{-1}\times a^{-1}\times b^{-1}$    (∵ $(mn)^a=m^a\timesn^a)$

$=a^{-1}\times b^{-1}\times a^{-1}\times b^{-1}$

$=a^{-1-1}\times b^{-1-1}$       (∵ $m^a\times m^b=m^{a+b})$

$=a^{-2}\times b^{-2}$

$=\frac{1}{a^{2}b^{2}}$  (∵ $m^{-a}=\frac{1}{m^a})$

Which should be the required answer.

Hope this helps.

Answer 2

Answer:

Step-by-step explanation: