Math, asked by rwitohiyamukherjee71, 8 months ago

A kite at the end of a 40 feet line is10 feet behind the runner. How high is the kite?

Answers

Answered by TheMoonlìghtPhoenix
9

Answer:

Step-by-step explanation:

ANSWER:-

\setlength{\unitlength}{27} \begin{picture}(7,7) \linethickness{1} \put(1,1){\line(1,0){4}} \put(5,1){\line(0,1){6}}\qbezier(1,1)(1,1)(5,7)\put(0.8,0.7){$ \bf B $}\put(5,0.7){$ \bf A $}\put(5,7){$ \bf C $}\put(2.2,0.7){$ \bf base = 10 \:feet$}\put(4.5,1){\line(0,1){0.5}}\put(4.5,1.5){\line(1,0){0.5}}\put( 0.5,4){$ \bf Hypotenuse  $}\put(0.5,3.5){$ \bf  = 40 feet $}\put(5.2,4){$ \bf Height  $}\put(5.2,3.5){$ \bf  = ? \:  cm $}\put(0,5.5){\boxed{$ \tt @MoonlightStarZ $}}\end{picture}[/tex]

  • Here the hypotenuse is 40 feet as the kite is behind the runner.
  • Also  10 feet line is behind the runner.
  • We need to find the height of the kite.

Pythagoras Theorem:-

\sf{Hypotenuse ^2 = Base^2+Height^2}

\sf{(40)^2 = Height^2+ (10)^2}

1600 = Height^2 +100

Height^2 = 1500

Height = 38.72 feet (approximately)

What this says?

  • The sum of squares of base and height of a right angle triangle is equal to the square of the hypotenuse of the same triangle.
Answered by EmpireDestroyer
11

Answer:

=> 38.72 ≈ 38.70 feet

Step-by-step explanation:

Let AB is the height of kite

Using Pythagoras theorem

=> AC² = BC² + AB²

Put the value

=> 40² = AB² + 10²

=> 1600 = AB² + 100

=> 1600-100 =AB²

=> 1500 = AB²

=> AB = √1500

=> AB = 38.72 ≈ 38.70 Feet

Similar questions