Math, asked by sianmariam, 8 months ago

A kite is flying in the sky when 100m of string is streched. It is at an angle of elevation of 45 degree. How high is the kite above from the ground? ​

Answers

Answered by reetavermaverma51
0

Step-by-step explanation:

Step-by-step explanation:

Since we have given that

Length of string of kite = 150 m

Angle of elevation formed by a kite with the horizontal = 60°

We need to find the height of kite.

Consider Δ ABC, as shown in the figure:

\begin{lgathered}\sin 60^\circ=\dfrac{AB}{AC}\\\\\dfrac{\sqrt{3}}{2}=\dfrac{AB}{150}\\\\\dfrac{150\sqrt{3}}{2}=AB\\\\75\sqrt{3}\ m=AB\end{lgathered}

sin60

=

AC

AB

2

3

=

150

AB

2

150

3

=AB

75

3

m=AB

Hence, height of the kite is 75√3 m.

Answered by sy999368
0

angle elevated means the angle made with horizontal hence by using sine of angle you can find height

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