A kite is flying in the sky when 100m of string is streched. It is at an angle of elevation of 45 degree. How high is the kite above from the ground?
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Step-by-step explanation:
Step-by-step explanation:
Since we have given that
Length of string of kite = 150 m
Angle of elevation formed by a kite with the horizontal = 60°
We need to find the height of kite.
Consider Δ ABC, as shown in the figure:
\begin{lgathered}\sin 60^\circ=\dfrac{AB}{AC}\\\\\dfrac{\sqrt{3}}{2}=\dfrac{AB}{150}\\\\\dfrac{150\sqrt{3}}{2}=AB\\\\75\sqrt{3}\ m=AB\end{lgathered}
sin60
∘
=
AC
AB
2
3
=
150
AB
2
150
3
=AB
75
3
m=AB
Hence, height of the kite is 75√3 m.
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angle elevated means the angle made with horizontal hence by using sine of angle you can find height
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