Question

A lab assistant has a solution of 50% acid and other which has 25% acid. How
much of each should be mixed to make 10 liters of a 40% acid solution?

Answer 1

heya !!!

50x + 25 (10-x) = 40 ( 10 )

50x + 250 - 25x = 400

50x-25x = 400 - 250

25x = 150

x = 150/6

x= 6

Use 6 litres of 50% acid and 4 litres of 25%

hope it helps u dear ^_^

Answer 2

Answer:

Let X be the amount of first solution and Y be the amount of second to be taken.

The amount of acid in x=0.5x

But another 50% has to be water.

The amount of water =0.5x.

The amount of acid in y=0.25y

The amount of water in y=0.75y

The total amount of acid required in final solution =0.4×10=4 litres and remaining 6 lit would be water.

Therefore,

0.5x+0.25y=4 .............(1)

Or,0.5x=4−0.25y

Similarly for water,

0.5x+0.75y=6 .................(2)

Substituting the value of 0.5x from Eq. (1) into Eq. (2) we have,

4−0.25y+0.75y=6

4+0.5y=6

y=4

x=6

Step-by-step explanation:

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