Question

a laber 10m long is leaning against a well the foot of the laber is 6m away from the well find the height up to which the laber reaches the wall

Answer 1

Use Pythagoras theorm.

Height

$= \sqrt{10 \times 10 - 6 \times 6 } \\ = \sqrt{64} \\ 8m$

Answer 2

Ans .with the help of P.T
10^2-6^2=height
100-36. =height
height. = 8 meter