Question

A labourer is engaged for 10 day on the condition that he receives 70 rupees for each day he work and has to pay fine 5 rupees for each day he remains absent. If he receives 475 rupees in all,for how many days does he remain absent?
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Answer 1

Answer:

3 days.

Step-by-step explanation:

Let he worked for x days and absent for (10-x) days.

So, according to question, he gets 70 rs for each working day and -5 for each absent days.

SO for working days he earns 70x and for absent he gave fines of

(10-x)  X  (-5),

So, the equation will be

70x+ (10-x)*(-5)=475

70x-50+5x=475

75x-50=475

75x=525

x=525/75=7

So, He worked only for 7 days, Now we need to calculate the number of days he was absent, so it will be 10–7=3 days.

The answer will be 3 days.