Math, asked by kingayaz382009, 7 months ago


A labourer was engaged for 30 days on the condition that he will get 260 for each day he works
will be fined 10 for each day he is absent. If he gets ? 1,700 at the end of the month, for hown
days did he remain absent?​

Answers

Answered by rajnisaklani414
6

Let number of days labourer did work =xdays

⇒ Then number of days he was absent =(30−x)days

⇒ Amount for days he worked =60x

⇒ Amount cut for days he was absent =10(30−x)=300−10x

According to the question,

60x−(300−10x)=1700

60x−300+10x=1700

50x−300=1700

50x=1400

x=

50

1400

∴ x=28days

⇒ Absent days =30−28=2days

∴ A labourer remain absent for 2days.

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Answered by anshikaminocha132
0

Answer:

The solution of the question..

Let number of days labourer did work =xdays

⇒ Then number of days he was absent =(30−x)days

⇒ Amount for days he worked =60x

⇒ Amount cut for days he was absent =10(30−x)=300−10x

According to the question,

60x−(300−10x)=1700

60x−300+10x=1700

50x−300=1700

50x=1400

x=

50

1400

∴ x=28days

⇒ Absent days =30−28=2days

∴ A labourer remain absent for 2days.

Step-by-step explanation:

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