Math, asked by yashwanth2234, 8 months ago

A labourer was engaged to serve on the condition that he would be paid Rs.20 for
each day of work but would be fined Rs.8 for each day of absenteeism. After 40
days he received Rs.380. How many days did he work and how many days was he
idle?​

Answers

Answered by aman2yadav123456
3

Answer:

he work on 25 days and he idle on 15 days

Step-by-step explanation:

let work days = x

and idle = y

20x-8y=380 eq 1

x+y= 40 eq 2

by eliminate method,

in eq 2 are multiple by 8

8x +8y =320

20 x -8y = 380

28x = 700

x = 25

put in eq 2

25 +y =40

y= 15

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