a ladder 10m long is leaning against a wall. the foot of the ladder is 8m away from the wall. find the height up to which the ladder reaches the wall
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Answered by
41
By Pythagoras theorem,
10²=8²+height upto which the ladder reaches²
100-64=height2²
36=height²
6m=height up to which the ladder reaches.
10²=8²+height upto which the ladder reaches²
100-64=height2²
36=height²
6m=height up to which the ladder reaches.
Answered by
22
Step-by-step explanation:
this question will be solved by Pythagoras theorem
the length of the ladder is given 10 metre
foot of the ladder away from the wall is 8 metre
(10)2-(8)2
10×10 - 8×8
100-64
=36 the square root of 36 will be 6
so answer is 6
we will take 10 square - 8 square means we have to multiply 10 × 10 and 8 × 8 so we will write 10 × 10 -8× 8 10 × 10 = 100 - 8 × 8 is equals to 64 so 100 -64 is equals to 36 now we will find out the square root of 36 so as we know the square root of 36 will be 6 because 6×6 is 36 answer will be 6
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