Math, asked by ramyagce6748, 1 year ago

a ladder 10m long is leaning against a wall. the foot of the ladder is 8m away from the wall. find the height up to which the ladder reaches the wall

Answers

Answered by abhi569
41
By Pythagoras theorem,

10²=8²+height upto which the ladder reaches²

100-64=height2²

36=height²

6m=height up to which the ladder reaches.
Answered by pearlroy
22

Step-by-step explanation:

this question will be solved by Pythagoras theorem

the length of the ladder is given 10 metre

foot of the ladder away from the wall is 8 metre

(10)2-(8)2

10×10 - 8×8

100-64

=36 the square root of 36 will be 6

so answer is 6

we will take 10 square - 8 square means we have to multiply 10 × 10 and 8 × 8 so we will write 10 × 10 -8× 8 10 × 10 = 100 - 8 × 8 is equals to 64 so 100 -64 is equals to 36 now we will find out the square root of 36 so as we know the square root of 36 will be 6 because 6×6 is 36 answer will be 6

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