Question

a ladder 10m long reaches a window 8m above the ground. find the distance of the foot of the ladder from base of the wall.​

Answer 1

Height of the ladder=10m (hypotenuse)
Length of the window=8m (perpendicular)

So we need to find the base

(H) ^ =(p)^ + (b) ^

(10*10) = (8*8) + (B)^
100= 64 + (B)^
100 - 64 =(B)^
36 = (B) ^
6m =base (square goes for square root)

So the distance of the foot of the ladder from the base of the wall is 6 m

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Answer 2

Answer:

Distance of the foot of the ladder from base of the wall = 6cm.

Step-by-step explanation:

Given:

• Length of the ladder =10m
• Distance between window and the ground =8m

Need to find:

• Distance of the foot of the ladder from base of the wall

Explanation:

Let AB be the ladder and BC be the wall with the window at B.

As it given that,

AB =10m

BC =8m

By applying Pythagoras theorem,

We get:

=> AB² = BC²+CA²

=> 10² = 8²+CA²

=> 100 = 64+CA²

=> 100-64 = CA²

=> 36 = CA²

=> √36 = CA

=> 6m = CA

Hence,Distance of the foot of the ladder from base of the wall is 6m.