A ladder 10m long was rested along a wall such that its top reaches to a height 8m from the ground along the wall how far is the foot of the ladder from the wall
nikhil6532:
the ans is 6 m acoriding to pythagoras thⁿ
Answers
Answered by
24
it is 6 meters away
bcoz the ladder and ground are perpendicular to each other
so then the height and distance from base are adjacent and opposite sides and the ladder is 10 meter
so let's apply Pythagoras theorem
therefore 10^2 = 8^2 +x^2
100 = 64 + x^2
100-64 = x^2
36 = x^2
6^2 = x^2
therefore x = 6
the distance from base is 6 meter away
hope u understand this
mark me as brainliest
bcoz the ladder and ground are perpendicular to each other
so then the height and distance from base are adjacent and opposite sides and the ladder is 10 meter
so let's apply Pythagoras theorem
therefore 10^2 = 8^2 +x^2
100 = 64 + x^2
100-64 = x^2
36 = x^2
6^2 = x^2
therefore x = 6
the distance from base is 6 meter away
hope u understand this
mark me as brainliest
Answered by
21
please mark as brailleast ❤️
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where I didn't understand because I am new and I have started a week Ago can you tell me
did I have done that
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