A ladder 13m long reaches a windows 5m above the ground, the distance of the foot of the ladder from the base of the wall is?
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Answer:
5 m matk as brainlist
Step-by-step explanation:
Length of ladder =13 m.
BC=12m,AC=13 m.
In ΔABC,
AB
2
+BC
2
=C
2
(Pythagoras theorem)
AB
2
=AC
2
−BC
2
=13
2
−12
2
=169−144
=25
∴AB=5 m.
∴ The distance of the foot of the ladder from the base of the wall =5 m
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