Question

a ladder 15m long reaches a window which is 9m above the ground on one side of the street. keeping its foot at the same point,the ladder is turned to the other side of the street to reach a window at 12m high. find the width of the street.​

Answer 1

Answer:

A ladder 15m long reaches a window which is a 9m above the ground on one side of the street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 12m high. Find the width of the street.

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ANSWER

In △ADC,

AD

2

+AC

2

=CD

2

9

2

+AC

2

=15

2

AC

2

=225−81

AC=12 m

In △BEC,

EC

2

=BC

2

+BE

2

15

2

=12

2

+BC

2

225−144=BC

2

BC=9 m

Width of the road = AC+BC = 12+9 = 21 m

Step-by-step explanation:

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Answer 2

Answer:

➜Given:

• a ladder 15m long reaches a window which is 9m above the ground on one side of the street.
• keeping its foot at the same point,the ladder is turned to the other side of the street to reach a window at 12m high.

➜To Find:

• the width of the street.

➜ Formula used:

$width = \frac{a}{l}$

➜Solution:

$In △ADC, \\ </p><p>AD {}^{2} +AC {}^{2} =CD {}^{ {}^{2} } \\ </p><p>92+AC {}^{2} =152 \\ </p><p>AC {}^{2} =225−81 \\ </p><p>AC=12 m \\ </p><p>In △BEC, \\ </p><p>EC {}^{2} =BC {}^{2} +BE {}^{2} \\ </p><p>152=122+BC {}^{2} \\ </p><p>225−144=BC {}^{2} \\ </p><p>BC=9 m \\ </p><p>Width \: of \: the \: road \\ = AC+BC = 12+9 = 21 m</p><p></p><p>$