Math, asked by minhaziyan, 5 months ago

A ladder 17m long rests against a vertical wall. If the foot of the ladder is 8m from the foot of the wall, find the distance of the other end of the ladder from the ground.
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Answers

Answered by shreshtha5532
2

Answer:

to find : the height of wall

Given: hypotenuse=17m

base=8m

By Pythagoras theorem

H^2 = P^2+ B^2

(17)^2 = P^2 + (8)^2

289 = P^2 + 64

289-64 = P^2

√225 = P

15m is equal to the distance of other end of the ladder from the ground.

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Answered by Anonymous
2

In this case, the ladder and the wall have formed a right angled triangle. That means, Pythagoras theorem can be applied here.

Hypotenuse = Length of ladder = 17 m

Base = Distance between the foot of the ladder to that of the wall = 8 m

Let, altitude, or distance of the other end of the ladder from the ground be = (a) m.

∵ Hypotenuse² = Base² + Altitude²,

∴ (17)² = a² + 8²

⇒a² = 17² - 8²

⇒a² = (17 + 8)(17 - 8) {a² - b² = (a + b)(a - b)}

[ALTER: ⇒a² = 289 - 64 = 225]

⇒a² = 225

⇒a = 15 m {Answer}

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