A ladder 20m long reached a window of a house 16m above the ground.the distance of the foot of ladder form the house will be.
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H from ground =16m
L of ladder=20m
It forms a right angled triangle
B= sq(H^2-p^2)
B=sq root(20^2-16^2)=12m
L of ladder=20m
It forms a right angled triangle
B= sq(H^2-p^2)
B=sq root(20^2-16^2)=12m
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