Question

A ladder 25 m long reaches window of building 20 m above the ground. Determine the distances from the foot of the ladder to the building

Answer 1

By using Pythagoras theorem,
H=25 m P=20 m
B^2 = H^2 - P^2
B^2 = 25^2 - 20^2
B^2 = 625 - 400
B^2 = 225
B = 15
Hence, distance between the foot of ladder and building is 15 m

Answer 2

Answer:

By using Pythagoras theorem,

H=25 m P=20 m

B^2 = H^2 - P^2

B^2 = 25^2 - 20^2

B^2 = 625 - 400

B^2 = 225

B = 15

Hence, distance between the foot of ladder and building is 15 m

Step-by-step explanation: