Math, asked by abdulparvez, 1 year ago

A ladder 25m long reaches a window of building 20m above the ground determine the distances of foot of the ladder from building

Answers

Answered by allymercymj
5
Let AB be the height of ladder
AC be the height of the building
And BC be the distance

By Pythagoras theorem
AB^2=AC^2+BC^2
25^2=20^2+BC^2
625=400+BC^2
625-400=BC^2
225=BC^2
√225=BC
15=BC
Therefore the distance of the foot from the building is 15 m
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Answered by ashvath7203
6
by Pythagoras Thorem,
AC*AC = AB*AB + BC*BC
(25)*(25) = (20)*(20) + BC*BC
625 = 400 + BC*BC
BC*BC = 625 - 400
BC*BC = 225
BC = 15m
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