a ladder 25m long reaches a window which is 24m above the ground on the side of the street Keeping the foot at the same point the ladder is turned to the other side of the street to reach a window 7m high find the width of the street
Answers
Find the horizontal width from the ladder to the window that is 24 m high:
a² + b² = c²
a² + 24² = 25²
a² = 25² - 24²
a² = 49
a = √49
a = 7 m
The width is 7 m
Find the horizontal width from the ladder to the window that is 7 m high:
a² + b² = c²
a² + 7² = 25²
a² = 25² - 7²
a² = 576
a = √576
a = 24 m
The width is 24 m
Find the total width:
Total width = 7 + 24 = 31 m
Answer: The width of the street is 31 m.
Answer:
Step-by-step explanation:
Let AB be the street and C be the foot of the ladder. Let D and E
Be the windows at the heights of 7m and 24m respectively.
From the ground.
Then, CD and CE are the two positions of the ladder.
In Triangle ACD
AC^2 + AD^2 = CD^2
AC^2 = (CD^2 – AD^2 )
= (25^2 – 7^ 2 ) m^2
= (625 – 49) m^2= 576m^2 = (24 m^2)
AC = 24 m
In Triangle CBE
CB^2 + BE^2 = CE^2
CB^2 = CE^2 - BE^2 = (252 – 242 ) m2
= (625 – 576) m^2= 49m^2 = (7m)^2
CB = 7 m
Therefore, breadth of the street = AB =AC + CB = 24m + 7m = 31m.