Question

A ladder 25m long reaches a window which is 7m above the ground, on one side of
the street. Keeping its foot at the same point, the lader is turned to the other side
of the street to reach a window at height of 24m. Find the width of the street.​

Answer 1

Answer:

actually here is the answer

Step-by-step explanation:

From figure △DAC and △EBC are right angled triangle.

So, by pythagorous theorem, we get

AC=24m And, CB=7m

Width of the street =AC+CB

⟹24+7=31m

HOPE THESE ANSWER HELPS U ☺️♥️

Answer 2

Answer:

• A ladder is 25 m long reaches a window that's 7 m high above the ground
• Then there's another ladder on the other side that is 24 m high
• Width of the street = ?

$\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(8,1)\qbezier(1,1)(1,1)(1,4)\qbezier(1,4)(1,4)(4,1)\qbezier(8,1)(8,1)(8,6)\qbezier(8,6)(8,6)(4,1)\put(0.8,0.5){\sf B}\put(3.9,0.5){\sf C}\put(7.9,0.5){\sf E}\put(0.9,4.2){\sf A}\put(7.9,6.2){\sf D}\end{picture}$

➝ AB = 7 cm

➝ AC = 25 cm

➝ DC = 25 cm

➝ DE = 24 cm

$\displaystyle\underline{\bigstar\:\textsf{According to the given Question :}}$

• So here we may use the Pythagoras theorem to find the length of BC and then the leng of CE

In ∆ABC

$\displaystyle\sf :\implies AB^2+BC^2 = AC^2$

$\displaystyle\sf :\implies 7^2+BC^2 = 25^2$

$\displaystyle\sf :\implies 49+BC^2 = 625$

$\displaystyle\sf :\implies BC^2 = 625-49$

$\displaystyle\sf :\implies BC^2 = 576$

$\displaystyle\sf :\implies BC = \sqrt{576}$

$\displaystyle\sf :\implies\underline{\boxed{\sf BC = 24 \ m}}$

In ∆DCE

$\displaystyle\sf :\implies DE^2+CE^2 = DC^2$

$\displaystyle\sf :\implies 24^2+CE^2 = 25^2$

$\displaystyle\sf :\implies 576+CE^2 = 625$

$\displaystyle\sf :\implies CE^2 = 625-576$

$\displaystyle\sf :\implies CE^2 = 49$

$\displaystyle\sf :\implies CE = \sqrt{49}$

$\displaystyle\sf :\implies\underline{\boxed{\sf CE = 7 \ m}}$

$\displaystyle\underline{\bigstar\:\textsf{Width of the street :}}$

$\displaystyle\sf \dashrightarrow Width = BC+CE$

$\displaystyle\sf \dashrightarrow Width = 24+7$

$\displaystyle\sf \dashrightarrow Width = 31 \ m$

$\displaystyle\therefore\:\underline{\textsf{The Width of the street will be \textbf{ 31 cm }}}$