nC(m+n,m)=(m+1)C(m+n,m+1) prove the identity
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Theorem 2.6 (Vandermonde identity) For integers N,M,n ≥ 0, one has n. ∑ k=0. (. N ... Hence we have to add |M ∩ P ∩ C| to make up for this. Formally ... (1 + xi)=(1+ x1)(1 + x2)... (1 + xk).
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