a ladder 25m long when set against the wall of a house just reaches a window at a height of 24m. how far is the lower end of the ladder from the base of the wall
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The ladder which is 25 m long is set against a wall of a house just about reaches a window at a height of 24 m above ground level.
Thus, the ladder makes right angled triangle.
In this situation, we will apply Pythagoras formula here.
H^2 = P^2 + B^2
Where H = height of ladder
P = height of window from the ground
B = distance of lower end of the ladder from the base of the wall.
Accordingly
25^2 = 24^2 + B^2
625 = 576 + B^2
B^2 = 625 - 576
B^2 = 49
B = √49
B = √7 × 7
B = 7
So, the distance between the foot of the ladder and the wall is equal to 7 meters.
Answer the lower end of the ladder is 7 meters from the base of the wall
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