a ladder 4.5 m long is placed against a wall in such a way that the foot of the ladder is 2.7 m away from the wall.find the height of the ball to which the ladder reaches.give the answer
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let the might be x
then
x^2 + 2.7^2 =4.5^2
x ^2 = 12.96
x = 3.6
then
x^2 + 2.7^2 =4.5^2
x ^2 = 12.96
x = 3.6
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