Math, asked by jadumusahari, 5 months ago

A ladder 4.5m long is placed against a wall in such a way that the foot of the ladder is 2.7m away from the wall. Find the height of the wall to which the ladder reaches. ​

Answers

Answered by parmarshrey21
10

Answer:

Step-by-step explanation:

By using Pythagoras theorem

Height of Wall Ladder reaches = √(Length of Ladder)^2 - (Distance of foot from wall)^2

=√(4.5)^2 - (2.7)^2

=√20.25-7.29

=√12.96

= 3.6 m

Hence, the ladder reaches a height of 3.6m to the wall.

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jadumusahari: Thanks for the answer
Answered by banisaha653
4

Step-by-step explanation:

ACCORDING TO THE GIVEN DIAGRAM:

LET THE LENGTH OF THE WALL BE X AND THE LENGTH OF LADDER BE THE HYPOTHENUSE SO THE DISTANCE FROM LADDER TO WALL WILL BE ITS BASE

Hypotenuse (H) =4.5 mtrs

base(B)=2.7 mtrs

height of wall(L) =x mtrs

According to Pythagoras theorem

(H)²=(L)²+(B)²

(4.5)²=(x)²+(2.7)²

(x)²=(4.5)²-(2.7)²

=20.25-7.29

=12.96

x=12.96

x=3.6

THEREFORE THE HEIGHT OF THE WALL IS 3.6mtrs

plss see the diagram and then understand the answer if u seethe diagram clearly then u will able to understand Pythagoras theorem very easily

thank you for asking me your lovingly bani saha

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