Question

A ladder 8 m long leans against a wall. The foot of the ladder is 130 cm from the wall. How far up the wall does e ladder reach?

Answer 1

to find the reach we have to a right angle triangle and pythogoarus theorem

hypotenuse = 8m =8*100=800cm

base =130cm

height=?

phythogoeus=

height = √ (hypotenus^2-base^2)

h=√(800^2-130^2)

h=√(640000-16900)

h=√623100

h=789.36

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Height\:of\:wall=7.89\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a 8 meter ladder leaned against the wall.The base of the ladder is 1.3 meter.

• We have to find the height of wall.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\:ladder=8\:m} \\ \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\:ladder=1.3\:m}\\\\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Height\:of\:wall= ?}$

• Accroding to given question :

$\bold{ By \: pythagoras \: theorem} \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \\ \\ : \implies {AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ : \implies {8}^{2} = {AB}^{2} + 1.3^{2} \\ \\ : \implies 64 = {AB}^{2} +1.69\\ \\ : \implies 64- 1.69= {AB}^{2} \\ \\ : \implies {AB}^{2} = 62.31 \\ \\ : \implies AB= \sqrt{62.31} \\ \\ \green{: \implies \text{AB = 7.89 \: m}}$