find the sum of 60terms of progression 3,5,7,...............
Answers
Answered by
2
Given :
AP : 3,5,7....
a = 3
common difference (d) = a2 - a1 = 5 - 3 = 2
no. of terms = 60
Sn = n/2 ( 2a + ( n - 1) d )
S60 = 60/2 ( 2(3) + (60 - 1) 2)
= 30 ( 6 + 59 × 2)
= 30 ( 6 + 118)
= 30 ( 124)
= 30× 124
= 3720
So the sum of 60 terms is 3720.
Hope it helps you.
AP : 3,5,7....
a = 3
common difference (d) = a2 - a1 = 5 - 3 = 2
no. of terms = 60
Sn = n/2 ( 2a + ( n - 1) d )
S60 = 60/2 ( 2(3) + (60 - 1) 2)
= 30 ( 6 + 59 × 2)
= 30 ( 6 + 118)
= 30 ( 124)
= 30× 124
= 3720
So the sum of 60 terms is 3720.
Hope it helps you.
Answered by
3
3 5 7
a= 3. d= 2
s = n/2( {2a +(n-1)d}
s= 60/2{2×3 +(60-1)2}
s = 30{6 +118)
=30×124
=3720
a= 3. d= 2
s = n/2( {2a +(n-1)d}
s= 60/2{2×3 +(60-1)2}
s = 30{6 +118)
=30×124
=3720
Similar questions