if pq parallael to rs and rs parallel to tu, then find angle rsp, psu and sut
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Hey mate
Here is your answer
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
It is given in the question that
PQ || RS and
RS || TU
So, PQ || RS || TU
angle QPS = angle RSP (interior alternate angles)
So, angle RSP = 100°
angle RSU + angle SUT = 180° ( co-interior angles)
=> angle SUT = 180° - 120° = 60°
angle PSU + angle RSP + angle RSU = 360° ( angle sum property )
=> angle PSU + 100° + 120° = 360°
=> angle PSU = 360° - 220° = 140°
Hence, angle RSP = 100°
angle PSU = 140°
angle SUT = 60°
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
Hope this helps!
Thank you
regrets
Sneha
Here is your answer
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
It is given in the question that
PQ || RS and
RS || TU
So, PQ || RS || TU
angle QPS = angle RSP (interior alternate angles)
So, angle RSP = 100°
angle RSU + angle SUT = 180° ( co-interior angles)
=> angle SUT = 180° - 120° = 60°
angle PSU + angle RSP + angle RSU = 360° ( angle sum property )
=> angle PSU + 100° + 120° = 360°
=> angle PSU = 360° - 220° = 140°
Hence, angle RSP = 100°
angle PSU = 140°
angle SUT = 60°
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
Hope this helps!
Thank you
regrets
Sneha
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