Question

A ladder is 50 feet and cast a 25 foot shadow. Mark is 6 feet how long would his shadow be?

Answer 1

Step-by-step explanation:

A building is 20 feet tall and casts a 12 foot shadow, and a person who is standing right next to the building casts a 3 ... Q. A ladder is 50 feet and casts a 25 foot shadow. Mark is 6 feet how long would his shadow be? answer choices. 25 feet.

Answer 2

Answer: The shadow of 6 feet Mark will be 3 feet.

What is proportion

A proportion is an equation based on the equality of two ratios.

Here it is given that:

A ladder is 50 feet and cast a 25 foot shadow : that is, for each feet of ladder $0.5$feet shadow is casted.

now, for 6 feet long Mark shadow will be:

$0.5 \times 6 \text { feet }=3 \text { feet }$

Therefore, the shadow of 6 feet Mark will be 3 feet.

Step-by-step explanation:

Step:1 Given:

Distance between the wall and foot of the ladder $=9.5 \mathrm{~m}$

Angle of elevation $(\theta)=60^{\circ}$

Length of the ladder $=\mathrm{L}=\mathrm{AC}$

Now, from fig. $\mathrm{ABC}$

$\triangle \mathrm{ABC}$ is a right angle triangle,

So,

$\begin{aligned}& \cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }} \\& \cos 60^{\circ}=\frac{\mathrm{BC}}{\mathrm{AC}} \\& \frac{1}{2}=\frac{9.5}{\mathrm{AC}} \\& \mathrm{AC}=2 \times 9.5=19 \mathrm{~m}\end{aligned}$

Thus, length of the ladder$(\mathrm{L})=19 \mathrm{~m}$

Step:2The length of the ladder $=15 \mathrm{~m}=\mathrm{AO}$

Angle made by the ladder with the wall $=60^{\circ}$

Let the height of the wall be h metres.

And the horizontal ground taken as $\mathrm{OX}$.

Then from the fig. we have,

In right$\triangle \mathrm{ABO}$, using trigonometric ratios

$\cos \left(60^{\circ}\right)=\mathrm{AB} / \mathrm{AO}$

$1 / 2=\mathrm{h} / 15$

$\mathrm{h}=15 / 2$

$\mathrm{h}=7.5 \mathrm{~m}$

Hence, the height of the wall is$7.5 \mathrm{~m}$

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