a ladder is leaning against a wall and reaches a window at a height of 15 feet. The foot of the ladder is placed 8 feet away from the wall . how long should the ladder be to reach the window.
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This requires a little use of the Pythagorean Theorem.
The length of the leaning ladder is the hypothenuse of the right triangle formed by the wall and the ladder.
Hyp. = 10 ft Say this is C
The ladder height up the wall = 8 ft. Say this A.
We need to find the other leg, say B ,of the right triangle.
C^2 = A^2 + B^2
10^2 = 8^2 + B^2
100 = 64 + B^2 => B^2 = 100 - 64 = 36
B^2 = 36 so, B = 6 The positive square root since length is positive.
B = 6 ft This is how far the ladder bottom is from the wall.
Double Check: 10^2 = 8^2 + 6^2 or 100 = 64 + 36 Ok. As, it should. This check could be done mentally.
In addition, this is a Pythagorean Triple. (6, 8, 10).
Answer: 6 ft
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Step-by-step explanation:
8²+ x² = 10²
64+x² = 100
x² = 36
x=6 ■
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