Question

a ladder is placed against a wall such that its foot is at a distance of 2.5 metre from the wall and its top reaches a window 6 metre above the ground find the length of the ladder.
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Answer 1

Answer:

Length of the ladder is 6.5m.

Step-by-step explanation:

Given:

• Distance of the foot of the ladder from the base of the wall = 2.5m
• Distance between the ground and the window = 6m

Need to find:

• Length of the ladder

Explanation:

Let AB be the ladder and CA be the wall with the window at A.

As it given that

BC = 2.5m

CA = 6m

By applying Pythagoras theorem,

We have:

=> AB² = BC²+CA²

=> AB² = (2.5)²+(6)²

=> AB² = 6.25+36

=> AB² = 42.25

=> AB = √42.25

=> AB = 6.5m

Hence, length of the ladder is 6.5m.

Answer 2

✞︎ Given :-

• The distance between foot of ladder and the wall is 2.5 m
• Height is 6 m

❦︎ To find :-

• The length of the ladder...

✯︎ Solution :-

From the figure ,

AB = 6m ; AC = 2.5m ; BC = X.....

In ∆ ABC , A = 90°

❁︎ By Pythagoras Therom ,

➪︎ ${h}^{2} = {s}^{2} + {s}^{2}$

➪︎ ${x}^{2} = {(2.5)}^{2} + {(6)}^{2}$

➪︎ ${x}^{2} = 6.25 + 36$

➪︎ ${x}^{2} = 42.25$

➪︎ $x = \sqrt{42.25}$

➪︎ $x = 6.5$

✰︎ Length of the ladder is 6.5 meters..