Question

A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 metre above the ground. find the length of the ladder.

Answer 1

It's a right angle triangle ....
so, the length of the ladder is √[(2.5)^2 + (6)^2] = √[ 42.25]^2 = 6.5 m

Answer 2

Hi!

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Let AB be the ladder and CA be the wall with the window at A

BC = 2.5 m

CA = 6 m

From Pythagoras theorem , We Have :

$AB^2 = BC^2 + CA^2$

= $(2.5)^2 + (6)^2$

= $42.25$

So , AB = 6.5

Thus , the length of the ladder is 6.5 m

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Thanks !!