Question

A LADDER IS PLACED AGAINST A WALL, WHICH IS 8.5M ABOVE THE GROUND.THE FOOT OF THE LADDER IS 2.5M AWAY FROM THE FOOT OF THE WALL. FIND THE LENGTH OF THE LADDER​

Answer 1

Answer:

${\green{\sf{\therefore Length\:of\:ladder=8.86m}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• According to given information it is clear that we have to find the length of ladder.

• So, length of wall is given and distance between foot of the wall to the foot of the ladder is given.

• We know that a wall is perpendicular so it makes 90° and ladder length is hypotenuse according to phythagoras theoram.

• According to given question :

$\bold{by \: phythaoras \: theoram :} \\ \to {h}^{2} = {p}^{2} + {b}^{2} \\ \to {h}^{2} = ({8.5})^{2} + ( {2.5})^{2} \\ \to {h}^{2} = 72.25 + 6.25 \\ \to {h}^{2} = 78.5 \\ \to h = \sqrt{78.5} \\ \bold{\therefore h = 8.86m}$

Answer 2

Answer :

$\textsf{\underline{\underline{Length\:of\:ladder = 8.86m}}}}$

Step-by-step explanation:

Given :

A ladder is placed against a wall, which is 8.6 cm above the ground.

The food of the ladder is 2.5 m away from the foot of the wall.

To Find :

The length of ladder.

Solution :

We know that :

★ Pythagorean theorem :

The area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides

Put the given values,

$\sf \\\implies {H}^{2}={P}^{2} + {B}^{2}\\ \\\implies {H}^{2}= ({8.5})^{2} +({2.5})^{2}\\ \\\implies H^{2}= 72.25+6.25\\ \\\implies H}^{2}=78.5\\ \\\implies H =\sqrt{78.5}\\ \\\implies H = 8.86m.$

$\bigstar\;\therefore\;\textsf{\underline{\underline{Length\:of\:ladder = 8.86m}}}}$