Question

A ladder leaning against a wall makes an angle of 60 degree with the round. If the length of the ladder is 19 M find the distance of the foot of the ladder from the wall.

Answer 1

let d be the distance between the foot of the ladder and the ground
ac=19m
ab is the wall
bc is the distance
cos 60=d/19
1/2=d/19
d=19/2
d=9.5
therefore the distance between the foot of the ladder and the ground is 9.5 m

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Distance\:between\:wall\:and\:foot\:of\:ladder = 9.5 \: m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a ladder leaning against a wall makes an angle of 60 degree with the ground. If the length of the ladder is 19 m.

• We have to find the distance of the foot of the ladder from the wall.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\:ladder=19\:m} \\ \\ : \implies \text{Angle\:of\:elevation=60^{\circ}}\\\\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\:ladder= ?}$

• Accroding to given question :

$\bold{In \: \triangle \: ABC} \\ : \implies cos \: \theta = \frac{\text{Base}}{\text{Hypotenuse}} \\ \\ : \implies cos \: 60^{ \circ} = \frac{AB}{AC} \\ \\ : \implies \frac{1}{2} = \frac{BC}{19} \\ \\ : \implies BC = \frac{19}{2} \\ \\ \green{ : \implies BC = 9.5 \: m} \\ \\ \green{\therefore \text{Distance\:between\:wall\:and\:foot\:of\:ladder = 9.5 \: m}}$