a ladder of 6.5 M long when set against the wall of a house reaches at a height of 2.5 cm how far is the foot of the ladder from the wall
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Let this whole figure be a right angled triangle
So,
I) hypotenuse or ladder = 6.5 m
II) Height = 2.5 m
III) distance between foot of ladder from the wall or base = unknown
Let this distance or base be x
According to Pythagoras Theorem
(Height)^2+ (Base)^2=Hypotenuse^2
So , this means
(2.5^2)+(x)^2= (6.5)^2
6.25+ x^2 = 42.25
Transposition
x^2= 42.25-6.25
x^2= 36
x= √36
x.= 6 m
Base or distance between the foot of ladder and the wall is 6 m
So,
I) hypotenuse or ladder = 6.5 m
II) Height = 2.5 m
III) distance between foot of ladder from the wall or base = unknown
Let this distance or base be x
According to Pythagoras Theorem
(Height)^2+ (Base)^2=Hypotenuse^2
So , this means
(2.5^2)+(x)^2= (6.5)^2
6.25+ x^2 = 42.25
Transposition
x^2= 42.25-6.25
x^2= 36
x= √36
x.= 6 m
Base or distance between the foot of ladder and the wall is 6 m
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